CodeBlock Arithmetic

[phase]

• {1o}3* should run the block 3 times.
• [123]{)o}/Should run the block for every object in the array with the object placed on the top of the stack, printing 234. (No idea how to implement this 😨)

Thoughts @kirbyfan64?

[refi64]

@phase I think I know how to implement the second one, but isn't the first basically the same thing as d? 3{1o}d

[phase]

@kirbyfan64 Oh yeah, forgot about that operator 🐼. I don't know what else it could be.

[refi64]

What if * is map and / is instead a "fold", like / in K?

[phase]

That makes sense, though using arithmetic operators on arrays already folds them.

[refi64]

@phase Well, / could be for arbitrary code blocks, not just arithmetic operations.

[phase]

So something like [421] {+3-}/ > 4+(2+(1-3)-3)-3?

[refi64]

@phase Either that (a right fold) or a left fold: (((1+2)-3)+4)-3. Which would you prefer? I believe Pyth and K do a left fold.

[phase]

We can just use whatever way [123]+ folds.

[refi64]

@phase That would be a left fold!

[phase]

% can be a filter, like [0101] {n>0} %. It would pop the stack after it runs each CB and if truthy, push that element to a separate array. I've got an idea on how to implement it.