giscus[bot]
bot Nov 4, 2025

consensus/consensus

构建大规模高可用的分布式系统

https://www.thebyte.com.cn/consensus/consensus.html

Replies: 1 comment

xizhedong
Nov 4, 2025 — with giscus

4 节点集群：Quorum 为 ⌈4/2⌉+1=3，允许 1 个节点故障。这里应该是向下取整后再加1吧

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